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Question:

The equivalent capacitance between A and B in the circuit given below is:

4.9 μF

5.4 μF

3.6 μF

2.4 μF

Solution:

C1=5+5+2=12μF
C2=4+2=6μF
1/CEq=1/6+1/12+1/6=5/12
CEq=2.4μF