Cu(NH3)42. So, metal rod M is Cu. The compound N is AgNO3 and the final solution contains [Ag(NH3)2]+ and [Cu(NH3)4]2+.

" /> Cu(NH3)42. So, metal rod M is Cu. The compound N is AgNO3 and the final solution contains [Ag(NH3)2]+ and [Cu(NH3)4]2+.

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Question:

The final solution contains:

[Pb(NH3)4]2+ and [CoCl4]2-

[Ag(NH3)2]+ and [Ni(NH3)6]2+

[Ag(NH3)2]+ and [Cu(NH3)4]2+

[Al(NH3)4]3+ and [Cu(NH3)4]2+

Solution:

Cu(M)+ + AgNO3 (aqueous colorless solution) → resultant solution Cu(NO3)2+ + AgNO3 Blue solution. Here it is considered: AgNO3 is not utilized in the reaction: AgNO3 + NaCl → AgCl↓ (O) + NaNO3 (White ppt). Solution containing white ppt. of AgCl also contains Cu(NO3)2. Which develops a deep blue colouration with aqueous NH3 solution. AgCl↓ (White) + 2NH3 (aq) → [Ag(NH3)2]+ Cu(NO3)2 (aq) + 4NH3 (aq) → Cu(NH3)42. So, metal rod M is Cu. The compound N is AgNO3 and the final solution contains [Ag(NH3)2]+ and [Cu(NH3)4]2+.