Question:

The force on a particle as a function of displacement x (in the x-direction) is given by F = 10 + 0.5x. The work done corresponding to the displacement of the particle from x = 0 to x = 2 units is?

21J

29J

25J

18J

Correct option is C. 21J

Given that F = 10 + 0.5x

Work done corresponding to the particle from x = 0 to x = 2 units is,

W = ∫₀² F.dx = ∫₀²(10 + 0.5x)dx = [10x + 0.5x²/2]₀² = 20 + 1 = 21J