The given circuit has two ideal diodes connected as shown in the figure below. The current flowing through the resistance R1 will be?

From figure, ideal diode D1 is reversed biased whereas ideal diode D2 is forward biased. Thus D1 acts as an open switch while D2 as a closed switch as shown in the equivalent circuit. Thus current flowing through R1, I = V/(R1 + R3) = 10/(2 + 2) = 2.5A