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Question:

The hybridizations of atomic orbitals of nitrogen in NO+2, NO− and NH+4 respectively are:

sp2, sp and sp3

sp, sp3 and sp2

sp, sp2 and sp3

sp2, sp3 and sp

Solution:

NO+2 contains 2 sigma bonds so hybridization is sp and shape is linear. NO− contains 3 sigma bonds so hybridization is sp2 and shape is trigonal. NH+4 contains 4 sigma bonds so hybridization is sp3 and shape is tetrahedral. Hence, option A is correct.