ΔG⁰<0, K<1
ΔG⁰>0, K<1
ΔG⁰<0, K>1
ΔG⁰<0, K=1
We know, ΔG = ΔG⁰ + RT lnK
At equilibrium, ΔG = ΔG⁰ + RT lnK = 0
If ΔG⁰ < 0, then RT lnK = -ΔG⁰ > 0, which implies lnK > 0, so K > 1.
If ΔG⁰ > 0, then RT lnK = -ΔG⁰ < 0, which implies lnK < 0, so K < 1.
If ΔG⁰ = 0, then RT lnK = 0, which implies lnK = 0, so K = 1.
Therefore, the incorrect match is ΔG⁰ < 0, K < 1.