loge|x³+1/x|+C
1/2loge(x³+1)²/|x³|+C
loge|x³+1|/x²+C
1/2loge|x³+1|/x²+C
Correct option is A. loge|x³+1/x|+C∫(2x³-1)/(x⁴+x)dx∫(2x-1/x²)/(x²+1/x)dxx²+1/x=t(2x-1/x²)dx=dt∫dt/t=ln(t)+C=ln(x²+1/x)+C