-x⁵(x⁵ + x³ + 1)² + C
x¹⁰/2(x⁵ + x³ + 1)² + C
x⁵/2(x⁵ + x³ + 1)² + C
-x⁵⁰/2(x⁵ + x³ + 1)² + C
∫2x¹² + 5x⁹(x⁵ + x³ + 1)³ dx = ∫2x¹² + 5x⁹(x⁵ + x³ + 1)³ dx = ∫2x⁷ + 5x⁴(x⁵ + x³ + 1)³ dx
Let x⁵ + x³ + 1 = t ⇒ ∫-dt/t³ = 1/2t² + c = x¹⁰/2(x⁵ + x³ + 1)² + c