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Question:

The kinetic energies of a planet in an elliptical orbit about the Sun, at positions A, B, and C are KA, KB, and KC respectively. AC is the major axis and SB is perpendicular to AC at the position of the Sun S as shown in the figure. Then,

KB<KA<KC

KA<KB<KC

KB>KA>KC

KA>KB>KC

Solution:

Kepler’s Law dAdt=constant T2∝r3dAdt=constant so KA>KB>KC option 4.