The length of the minute hand of a clock is 14cm. If the minute hand moves from 1 to 10 on the dial, then an area of ...................cm² will be covered.
154
462
616
308
Solution:
For r=14cm and θ=360 × 9/12 = 270° Area of the minor sector = πr²θ/360 = 22/7 × 14 × 14 × 270/360 = 462cm²