The lengths of two parallel chords of a circle are 6cm and 8cm. If the smaller chord is at distance 4cm from the centre, what is the distance of the other chord from the centre?

There are two parallel chords of length 8cm and 6cm. The distance between the center and the shortest chord (6cm chord) is 4cm. So, the perpendicular distance from the center to the shortest chord is 4cm. The perpendicular line from the center to the chord divides the chord into two equal parts. So, the radius of the circle is √(3² + 4²) = 5. Since the radius is 5, the distance from the center to the largest chord is √(5² - 4²) = 3.