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Question:

The magnetic potential energy stored in a certain inductor is 25mJ, when the current in the inductor is 60mA. This inductor is of inductance.

138.88H

0.138H

13.89H

1.389H

Solution:

Energy stored in a Inductor is given as
U=1/2LI²
L=2UI²
L=2 × 25 × 10⁻³ /(60 × 10⁻³) ²
L=13.89H