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Question:

The major product obtained in the following reaction is: C6H5CH=CHC6H5, (+)C6H5CH(OtBu)CH2C6H5, (±)C6H5CH(OtBu)CH2C6H5, (−)C6H5CH(OtBu)CH2C6H5

C6H5CH=CHC6H5

(+)C6H5CH(OtBu)CH2C6H5

(±)C6H5CH(OtBu)CH2C6H5

(−)C6H5CH(OtBu)CH2C6H5

Solution:

Alkene is the product as bulky hindered base and secondary alkyl bromide favors elimination over substitution. Hence, the option (A) is the correct answer.