The molar conductivity of a 0.5 mol/dm³ solution of AgNO₃ with electrolytic conductivity of 5.76 × 10⁻³ Scm⁻¹ at 298 K is :

Given:
Concentration (C) = 0.5 mol/dm³
Electrolytic conductivity (κ) = 5.76 × 10⁻³ Scm⁻¹
Temperature (T) = 298 K
Molar conductivity (Λₘ) is given by the formula:
Λₘ = κ × 1000 / C
Substituting the given values:
Λₘ = (5.76 × 10⁻³ Scm⁻¹) × (1000 cm³/dm³) / (0.5 mol/dm³)
Λₘ = (5.76 × 10⁻³ × 1000) / 0.5 Scm²/mol
Λₘ = 5.76 × 2000 / 1000 Scm²/mol
Λₘ = 11.52 Scm²/mol
Therefore, the molar conductivity of the 0.5 mol/dm³ solution of AgNO₃ is 11.52 Scm²/mol.