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Question:

The molar conductivity of a 1.5M solution of an electrolyte is found to be 138.9 S cm² mol⁻¹. Calculate the conductivity of this solution.

Solution:

Molar Conductivity, k = Conductivity/Concentration

κ = kC

Conductivity, κ = k × C = 138.9 (S cm² mol⁻¹) × 1.5 (mol/L) × 1000 (cm³/L) = 208350 S cm⁻¹ = 208.35 S cm⁻¹

Therefore, the conductivity of the solution is 208.35 S cm⁻¹ (Siemens per centimeter).