The M−O−M bond angles in M₂O (where M is halogen) is in the order:

In OF₂, repulsion between the lone pairs is greater than between bond pair since electrons are away from O and nearer to F. In Cl₂O, bonding electrons are nearer to O than to Cl, so the bond angle is greater than 109°28'. In Br₂O, the bonding electrons are more closer to oxygen than in Cl₂O, so the bond angle is the largest (116°). Bond angle order will be Br₂O>Cl₂O>F₂O. Option A is correct.