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Question:

The moment of the force, F = 4i + 5j + 6k at (2, 0, 3), about the point (2, 0, 0) is given by

12i + 8j + 12k

12i + 8j - 12k

12i - 8j + 12k

8i - 12j + 12k

Solution:

where, r = 0i + 0j - 0k
Moment of force = r × F = [0i + 0j - 0k] × [4i + 5j + 6k] = 12i + 8j + 12k