The number of electrons delivered at the cathode during electrolysis by a current of 1 ampere in 60 seconds is :(charge on an electron is 1.60 × 10⁻¹⁹ C)

Q = ne
Q is the amount of electricity passed
n is the number of electrons liberated at cathode
e the charge of electron
i × t = ne (Q = i × t)
n = i × t / e
n = 1 × 60 / (1.6 × 10⁻¹⁹)
n = 3.75 × 10²⁰