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Question:

The number of hexagonal faces that are present in a truncated octahedron is:

11

10

8

9

Solution:

The number of hexagonal faces that are present in a truncated octahedron is 8. A truncated octahedron is constructed from a regular octahedron with side length 3a by the removal of six right square pyramids, one from each point. It has 6 squares and 8 hexagons.