Eduprobe
Question:
The number of terms in the expansion of (1+x)101(1+x2-x)100 in power of x is :
301
302
202
101
Solution:
(1+x)101(1−x+x2)100can be written as=(1+x)(1+x)100(1−x+x2)100
301
302
202
101
(1+x)101(1−x+x2)100can be written as=(1+x)(1+x)100(1−x+x2)100