The order of stability of the following tautomeric compounds is:
CH2=OH|C−CH2−O||C−CH3⇌CH3−O||C−CH2−O||C−CH3⇌CH3−OH|C=CH−O||C−CH3

The order of stability of the tautomeric compounds is
III>II>I
The tautomer III has the highest stability as the C=C double bond and C=O double bond are conjugated which results in delocalization and hydrogen bonding.
Tautomer I is less stable than tautomer II as the enol is less stable than keto group.
CH3−OH|C=CH−O||C−CH3 > CH3−O||C−CH2−O||C−CH3 > CH2=OH|C−CH2−O||C−CH3
III II I
Option B is correct.