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Question:

The order of the oxidation state of the phosphorus atom in H3PO2, H3PO4, H3PO3, and H4P2O6 is:

H3PO2>H3PO3>H4P2O6>H3PO4

H3PO4>H4P2O6>H3PO3>H3PO2

H3PO4<H3PO2<H3PO3<H3P2O6

H3PO4>H3PO2>H3PO3>H3P2O6

Solution:

Compound Oxidation state of P
H3PO2 +1
H3PO4 +5
H3PO3 +3
H4P2O6 +4
Hence the correct order of oxidation state of phosphorous atom is-
H3PO4>H4P2O6>H3PO3>H3PO2
Hence, the correct option is D