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Question:

The pair(s) of coordination complexes/ions exhibiting the same kind of isomerism is(are): [Cr(NH3)5Cl]Cl2 and [Cr(NH3)4Cl2]Cl; [Co(NH3)4Cl2]+ and [Pt(NH3)2(H2O)Cl]+; [CoBr2Cl2]2− and [PtBr2Cl2]2−; [Pt(NH3)3(NO3)]Cl and [Pt(NH3)3Cl]Br

[Cr(NH3)5Cl]Cl2and[Cr(NH3)4Cl2]Cl

[CoBr2Cl2]2−and[PtBr2Cl2]2−

[Pt(NH3)3(NO3)]Cland[Pt(NH3)3Cl]Br

[Co(NH3)4Cl2]+and[Pt(NH3)2(H2O)Cl]+

Solution:

The pairs of coordination complexes/ions exhibiting the same kind of isomerism are:
Octahedral [Co(NH3)4Cl2]+ and square planar [Pt(NH3)2(H2O)Cl]+ which shows geometrical (cis-trans) isomerism.
Square planar [Pt(NH3)3(NO3)]Cl and square planar [Pt(NH3)3Cl]Br shows ionization isomerism.
The pairs of coordination complexes/ions NOT exhibiting the same kind of isomerism are:
[Cr(NH3)5Cl]Cl2 neither shows structural nor stereoisomerism.
[Cr(NH3)4Cl2]Cl shows geometrical (cis trans) isomerism.
Tetrahedral [CoBr2Cl2]2− and square planar [PtBr2Cl2]2− do not show the same type of isomerism.
Hence, options B and D are correct.