The phase space diagram for a ball thrown vertically up from ground is ABCD?

At a particular time say t=0s, the particle has velocity +v and thus momentum p(t=0)=+mv. Also, displacement is 0. At time t, the particle reaches maximum height with displacement x=h. Here, velocity v=0. Now, when the particle comes back to its initial position, velocity is reversed i.e. v=−v and thus, momentum, p=−mv. So, we get the graph corresponding to Option D.