v=√(kR/m)
v=√(kmR)
L=√(mkR²)
L=√(mk²R²)
Given potential energy V = kr²/2
F = -kr (towards centre) [F = -dV/dr]
At r = R, kR = mv²/R [Centripetal force]
where v is the speed of the particle
⇒ velocity v = √(kR²/m) = √(kR/m)
Angular momentum L = mvr = mR√(kR/m) = √(mkR³)
Therefore, v = √(kR/m) and L = √(mkR³)