2.2×10⁶Pa
2.2×10⁸Pa
2.2×10⁷Pa
2.2×10⁹Pa
We have change in length due to the change in temperature (considering no obstruction)
ΔL = αLΔT
or ΔL = 1.1×10⁻⁵ × 0.10 × 100 = 1.1×10⁻⁴m
Now pressure which needs to be applied would be given using
F/A = Pressure = ΔL × Y/L = 1.1×10⁻⁴ × 2 × 10¹¹/0.1 (Here ΔL is the expansion prevented)
= 2.2×10⁸Pa