The products obtained when chlorine gas reacts with cold and dilute aqueous NaOH are:
Cl⁻andClO⁻
Cl⁻andClO⁻
ClO⁻andClO⁻
ClO⁻andClO⁻
Solution:
2NaOH(cold)+Cl₂→NaCl+NaClO+H₂O The products obtained when chlorine gas reacts with cold and dilute aqueous NaOH are Cl⁻ and ClO⁻. Hence, option A is the correct answer.