The projections of a vector on the three coordinate axes are 6, -7, 2 respectively. The direction cosines of the vector are?

Projection of a vector on coordinate axes are x2-x1, y2-y1, z2-z1
So, we have
x2-x1=6, y2-y1=-7, z2-z1=2
√(x2-x1)²+(y2-y1)²+(z2-z1)² = √36+49+4=√89
The D.C.'s are 6/√89, -7/√89, 2/√89
However, none of the options match this result. Let's re-examine the problem statement.
Assuming the projections are given as 6, -7, 2. Then the magnitude of the vector is √(6² + (-7)² + 2²) = √89.
The direction cosines are then: 6/√89, -7/√89, 2/√89.
Approximating these values:
6/√89 ≈ 0.636
-7/√89 ≈ -0.744
2/√89 ≈ 0.212
Comparing to the given options, none match precisely. There might be an error in the question or the options provided.