The ratio of mass densities of nuclei of ^40Ca and ^16O is close to:

Correct option is A. 1
ρ= Mass/Volume = m/[(4/3)πr³] = r₀A^(1/3)
r = radius of nucleus
A = Atomic number
r₀ = constant
ρ ∝ Mass/A
For Oxygen, Z=8, A=16
For Calcium, Z=20, A=40
ρ_O/ρ_Ca = (A_O/A_Ca) = (16/40) = 0.4 ≈ 0.1