The ratio of the specific heats Cp/Cv = γ in terms of degree of freedom (n) is given by:
(1+1n)
(1+n2)
(1+2n)
(1+n3)
Solution:
The internal energy for 1 mole of gas is given as U = n/2 RdT = CvdT where n is degrees of freedom Cp − Cv = R Cp = (1 + n/2)R and Cp/Cv = γ = (1 + n/2)R / (n/2)R = 1 + 2/n