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Question:

The ratio of wavelengths of the last line of Balmer series and the last line of Lyman series is 0.5124

1

2

0.5

4

Solution:

λ₁ = 109678[1/n₂² - 1/n₁²] last balmer line
λ₁ = 109678[1/2² - 1/∞] last laymen line
λ = 109678[1/1² - 1/∞]
λ₁:λ₂ = 4