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Question:

The ratio of work done by an ideal monoatomic gas to the heat supplied to it in an isobaric process is:

2/3

3/2

3/5

2/5

Solution:

In isobaric process, heat supplied is Q = nCpΔT. Work done is W = PΔV = nRΔT. Hence ratio is R/Cp = R/(γR) = 1/γ = 2/5 [∵ γ = 5/3, for a monoatomic gas]