T1=T2
ΔUisothermal>ΔUadiabatic
T3>T1
Wisothermal>Wadiabatic
(A) For an Isothermal process, the temperature is constant ∴T1=T2 (B) Adiabatic process temp. decreases. ∴T3<T1 (C) In Wisothermal, ΔU=0, so energy gets converted into work done whereas for in the adiabatic process Q=0 ∴Wisothermal>Wadiabatic (D) For isothermal process change in internal energy is constant but not in the adiabatic process. Thus ΔUisothermal=0, ΔUadiabatic=-ve, so ∴ΔUisothermal>ΔUadiabatic Hence, the correct options are A, C and D