The r.m.s. value of potential difference V shown in the figure is
V0
V0/2
V0/√3
V0/√2
Solution:
Vrms=√(1/T∫V²dt) where T is the period of the waveform. In this case, V = V0 for half the period (T/2) and V = 0 for the other half. Therefore, Vrms = √(1/T ∫(T/2)V0²dt) = √(V0²/2) = V0/√2