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Question:

The r.m.s. value of potential difference V shown in the figure is

V0

V0/2

V0/√3

V0/√2

Solution:

Vrms=√(1/T∫V²dt) where T is the period of the waveform.
In this case, V = V0 for half the period (T/2) and V = 0 for the other half.
Therefore, Vrms = √(1/T ∫(T/2)V0²dt) = √(V0²/2) = V0/√2