The second overtone of an open pipe has the same frequency as the first overtone of a closed pipe 2m long. The length of the open pipe is: 4 m, 1 m, 2 m, 8 m
8 m
1 m
4 m
2 m
Solution:
Given : Length of the closed pipe L'=2m First overtone frequency of closed pipe ν'=3v/4L' Let the length of the open organ pipe be L Second overtone of an open pipe i.e m=3 ν3=3v/2L But ν3=ν' ∴3v/2L=3v/4L' ⇒L=2L'=2×2=4m