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Question:

The self inductance of a coil having 500 turns is 50 mH. The magnetic flux through the cross-sectional area of the coil while current through it is 8 mA is found to be?

4µWb

4×10⁻⁸Wb

0.04Wb

40mWb

Solution:

The magnetic flux through an inductor is the self inductance of coil times the current through it.Thus Φ=LI=50×10⁻³H×8×10⁻³A=4×10⁻⁴Wb