The self inductance of a coil having 500 turns is 50mH. The magnetic flux through the cross-sectional area of the coil while current through it is 8mA is found to be?

Correct option is A. 4×10−4Wb
Given that,
Number of turns N = 500
Self inductance L = 50×10−3 H
Current I = 8×10−3 A
The magnetic flux through an inductor is the self inductance of coil times the current through it.
The flux is ϕ = LI
ϕ = 50×10−3×8×10−3
ϕ = 4×10−4 Wb
So, the magnetic flux is 4×10−4 Wb
Hence, A is the correct option.