loge√√√2−y2−x√√√=2(y−1)
loge√√√2−x2−y√√√=x−y
−loge√√√1+x−y1−x+y√√√=x+y−2
−loge√√√1−x+y1+x−y√√√=2(x−1)
x−y=t⟹dydx=1−dtdx⟹1−dtdx=t2⟹∫dt1−t2=∫1dx⟹12ln(1+t1−t)=x+λ⟹12ln(1+x−y1−x+y)=x+λ