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Question:

The specific conductance of a N/10 KCl at 25°C is 0.0112 ohm⁻¹cm⁻¹. The resistance of a cell containing this solution at the same temperature was found to be 55 ohm. The cell constant will be:

0.616 cm⁻¹

616 cm⁻¹

6.16 cm⁻¹

0.0616 cm⁻¹

Solution:

We know that
specific conductance = Cell constant × conductance
∴ Cell constant = Resistance × specific conductance
G* = 55 × 0.0112 = 0.616 cm⁻¹
Hence, the correct option is 0.616 cm⁻¹.