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Question:

The standard Gibbs energy change at 300 K for the reaction 2A⇌B+C is 2494.2 J. At a given time, the composition of the reaction mixture is [A] = 12, [B] = 2 and [C] = 12. The reaction proceeds in the: [R=8.314 J/K/mol, e=2.718]

reverse direction becauseQ>Ke

forward direction becauseQ<Ke

forward direction becauseQ>Ke

reverse direction becauseQ<Ke

Solution:

The expression for the reaction quotient Q is Q=[B][C]/[A]2
Substitute values in the above expression.
Q = (2)(12)/(12)2 = 24/144 = 1/6 = 0.1667
ΔG° = -RTlnKe
2494.2 J = -8.314 J/K/mol × 300 K × lnKe
lnKe = -2494.2/(8.314 × 300) = -0.999 ≈ -1
Ke = e-1 = 0.3679
Since Q<Ke, the reaction will proceed in the forward direction.