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Question:

The stopping potential in an experiment on photoelectric effect is 1.5V. What is the maximum kinetic energy of the photoelectrons emitted?

Solution:

Photoelectric cut-off voltage , Vo = 1.5V
K.E = eV
where e = charge of an electron = 1.6 × 10⁻¹⁹ C
so, K.E = 1.6 × 10⁻¹⁹ × 1.5
K.E = 2.4 × 10⁻¹⁹ J