The sum of 3 consecutive multiples of 8 is 888. Find the multiples

Let 3 consecutive multiples of 8 be 8x, 8(x+1), 8(x+2)
Sum = 8x + 8(x+1) + 8(x+2) = 888
8(x + x + x + 1 + 2) = 888
3(x+1) = 111
x + 1 = 37
3x + 1 = 37
3x = 36
x = 12
First multiple = 8x = 8 × 12 = 96
Second = 8(x+1) = 8 × 13 = 104
Third = 8(x+2) = 8 × 14 = 112