1/2(350)
1/2(350+1)
1/2(350-1)
1/2(250+1)
(1√x)50=50C0C1(2√x)+50C2(2√x)2.we need to find sum of even forms, soPut√x=1⟹(1)50=1=50C0C1(2)+50C2(2)2 (1)and√x=⟹(1+2)50=350=50C0+50C12+50C2(2)2.. (2)Adding (1) and (2) we get,350+1=2(50C0+50C2(2)2+)⇒(50C0+50C2(2)2+)=12(1+350)