The sum of the intercepts on the coordinate axes of the plane passing through the point (a, a, 2) and containing the line joining the points (1, b, 2) and (1, 1, 1) is?

| x-x1 y-y1 z-z1 | = 0
| x2-x1 y2-y1 z2-z1 |
| x3-x1 y3-y1 z3-z1 |

| x+2 y+2 z-2 | = 0
| 0 b-1 0 |
| 0 0 -1 |

=> x+2y+2z -6 = 0 => (x/6) + (y/3) + (z/3) = 1
Sum of intercepts = 6 + 3 + 3 = 12