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Question:

The sum of the number of lone pairs of electrons on each central atom in the following species is: [TeBr6]2−, [BrF2]+, SNF3, and [XeF3]−. [Atomic numbers: N=7, F=9, S=16, Br=35, Te=52, Xe=54]

Solution:

The sum of the number of lone pairs of electrons on each central atom in the given species is 1+2+0+3=6.
Te atom in [TeBr6]2− has 1 lone pair of electrons.
Br atom in [BrF2]+ has 2 lone pairs of electrons.
S atom in SNF3 has 0 lone pair of electrons.
Xe atom in [XeF3]− has 3 lone pairs of electrons.