The sum of the series 2.^20C_0 + 5.^20C_1 + 8.^20C_2 + 11.^20C_3 + .... + 62.^20C_20 is equal to :

Correct option is B.2252.20C0+5.20C1+8.C2+11.20C3++62.∑r=020(3r+2)20C=3∑r=020.20Cr+2∑r=020203∑r=020r(20r)19Cr−1;+2.220=60.219+2.220=225