The sum of the solution of the equation |√x - 2| + √x(√x - 4) + 2 = 0 is equal to:

Correct option is C. 10
|√x - 2| + x(√x - 4) + 2 = 0
=> |√x - 2| + x² - 4x + 2 = 0
=> |√x - 2|² + |√x - 2| - 2 = 0
Let |√x - 2| = y
y² + y - 2 = 0
(y + 2)(y - 1) = 0
y = -2 or y = 1
Since y = |√x - 2|, y cannot be negative.
Therefore, y = 1
|√x - 2| = 1
√x - 2 = 1 or √x - 2 = -1
√x = 3 or √x = 1
x = 9 or x = 1
Sum = 10