The tangent and the normal lines at the point (3,1) to the circle x² + y² = 4 and the x-axis form a triangle. The area of this triangle (in square units) is:
13
13
43
23
Solution:
Correct option is D. 23 Given x² + y² = 4 equation of tangent → 3x + y = 4 (1) equation of normal x − 3y = 0.. (2) Coordinate of T(4/3, 0) ∴Area of triangle = 23