The taxi fare in a city is as follows: For the first kilometre, the fare is 8 and for the subsequent distance it is 5 per km. Taking the distance covered as x km and total fare as Rs. y, write a linear equation for this information and draw its graph.

Taxi fare for first kilometer=Rs.8
Taxi fare for subsequent distance=Rs.5
Total distance covered=x
Total fare=y
Since the fare for first kilometer=Rs.8
According to problem,Fare for(x-1)kilometer=5(x-1)
So, the total fare y=5(x-1)+8
→y=5(x-1)+8
→y=5x-5+8
→y=5x+3
Hence, y=5x+3 is the required linear equation.
Now the equation is y=5x+3.. (1)
Now, putting the value x=0 in (1)
y=5×0+3
y=0+3=3
So the solution is (0,3)
Putting the value x=1 in (1)
y=5×1+3
y=5+3=8. So the solution is (1,8)
Putting the value x=2 in (1)
y=5×2+3
y=10+3=13. So the solution is (2,13)