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Question:

The temperature difference of 120oC is maintained between two ends of a uniform rod AB of length 2L. Another bent rod PQ, of same cross-section as AB and length 3L/2, is connected across AB (see figure). In steady state, the temperature difference between P and Q will be close to:

35oC

45oC

60oC

75oC

Solution:

ΔTReq.=I=(120)5/8R=120×5/8R
ΔTPQ=120×5/8R×3/5R=360/8=45oC